/*3*/ Console::WriteLine("{0}{1} found", word, (dictionary->Contains(word) ? "" : " not"));
　}
}

　　插2：使用反串行化进行字典查找

Dictionary contains 20159 entries
Enter a word: house
house found
Enter a word: houses
houses not found
Enter a word: brick
brick found
Enter a word: manly
manly not found

　　此处最重要的是，我们能在单个函数调用中，串行、反串行化任意大小、任意复杂性的对象。


　处理多个句柄

　　当我们传递一个对象的句柄给Serialize时，似乎会在底层对对象进行一个复制，那么，实际情况真的是这样吗？假设我们把包含有多个句柄的一个对象写入到其他对象中，或者我们调用Serialize两次，每次都给它同一个对象的句柄呢？我们真的想得到同一对象的多个副本吗？在例4中演示了这个过程：

　例4：

using namespace System;
using namespace System::IO;
using namespace System::Runtime::Serialization::Formatters::Binary;

/*1*/ [Serializable]
ref class Employee { /* */};

int main()
{
　Employee^ emp1 = gcnew Employee();
　Employee^ emp2 = gcnew Employee();
　Employee^ emp3 = emp2;
　/*2a*/ Console::WriteLine("emp1 == emp2 is {0}", (emp1 == emp2));
　/*2b*/ Console::WriteLine("emp2 == emp3 is {0}", (emp2 == emp3));
　/*2c*/ Console::WriteLine("emp1 == emp3 is {0}", (emp1 == emp3));

　array<Object^>^ list = gcnew array<Object^>(2);
　list[0] = emp1;
　list = list[0];
　/*2d*/ Console::WriteLine("list[0] == list is {0}", (list[0] == list));
　/*2e*/ Console::WriteLine("list[0] == emp1 is {0}", (list[0] == emp1));
　/*2f*/ Console::WriteLine("list == emp1 is {0}", (list == emp1));

　//将数据串行化到文件

　BinaryFormatter^ formatter = gcnew BinaryFormatter;
　Stream^ file = File::Open("Sr03.ser", FileMode::Create);

　/*3a*/ formatter->Serialize(file, emp1);
　/*3b*/ formatter->Serialize(file, emp2);
　/*3c*/ formatter->Serialize(file, emp3);
　/*3d*/ formatter->Serialize(file, list);

　file->Close();

　//从文件中反串行化数据--即读取数据

　file = File::Open("Sr03.ser", FileMode::Open);

　/*4a*/ emp1 = static_cast<Employee^>(formatter->Deserialize(file));
　/*4b*/ emp2 = static_cast<Employee^>(formatter->Deserialize(file));
　/*4c*/ emp3 = static_cast<Employee^>(formatter->Deserialize(file));
　/*4d*/ list = static_cast<array<Object^>^>(formatter->Deserialize(file));

　file->Close();

　/*5a*/ Console::WriteLine("emp1 == emp2 is {0}", (emp1 == emp2));
　/*5b*/ Console::WriteLine("emp2 == emp3 is {0}", (emp2 == emp3));
　/*5c*/ Console::WriteLine("emp1 == emp3 is {0}", (emp1 == emp3));
　/*5d*/ Console::WriteLine("list[0] == list is {0}", (list[0] == list));
　/*5e*/ Console::WriteLine("list[0] == emp1 is {0}", (list[0] == emp1));
　/*5f*/ Console::WriteLine("list == emp1 is {0}", (list == emp1));
}

　　在本例中，我们想对Employee类型（在标记1中的用户自定义类型）的对象进行串行化，必须把Serializable属性附加到这个类型上。如果我们试图串行化一个没有标明此属性的类对象，将会抛出一个System::Runtime: