VB中实现MD5加密

= UnsignedToLong(1732584193#)
    State(2) = UnsignedToLong(4023233417#)
    State(3) = UnsignedToLong(2562383102#)
    State(4) = UnsignedToLong(271733878#)
End Sub

''
'' MD5 Final
''
Public Sub MD5Final()
    Dim dblBits As Double
    
    Dim padding(72) As Byte
    Dim lngBytesBuffered As Long
    
    padding(0) = &H80
    
    dblBits = ByteCounter * 8
    
    '' Pad out
    lngBytesBuffered = ByteCounter Mod 64
    If lngBytesBuffered <= 56 Then
        MD5Update 56 - lngBytesBuffered, padding
    Else
        MD5Update 120 - ByteCounter, padding
    End If
    
    
    padding(0) = UnsignedToLong(dblBits) And &HFF&
    padding(1) = UnsignedToLong(dblBits) \ 256 And &HFF&
    padding(2) = UnsignedToLong(dblBits) \ 65536 And &HFF&
    padding(3) = UnsignedToLong(dblBits) \ 16777216 And &HFF&
    padding(4) = 0
    padding(5) = 0
    padding(6) = 0
    padding(7) = 0
    
    MD5Update 8, padding
End Sub

''
'' Break up input stream into 64 byte chunks
''
Public Sub MD5Update(InputLen As Long, InputBuffer() As Byte)
    Dim II As Integer
    Dim I As Integer
    Dim J As Integer
    Dim K As Integer
    Dim lngBufferedBytes As Long
    Dim lngBufferRemaining As Long
    Dim lngRem As Long
    
    lngBufferedBytes = ByteCounter Mod 64
    lngBufferRemaining = 64 - lngBufferedBytes
    ByteCounter = ByteCounter + InputLen
    '' Use up old buffer results first
    If InputLen >= lngBufferRemaining Then
        For II = 0 To lngBufferRemaining - 1
            ByteBuffer(lngBufferedBytes + II) = InputBuffer(II)
        Next II
        MD5Transform ByteBuffer
        
        lngRem = (InputLen) Mod 64
        '' The transfer is a multiple of 64 lets do some transformations
        For I = lngBufferRemaining To InputLen - II -