set rowcount n
select * from 表变量 order by columnname desc
2.
select top n * from (select top m * from tablename order by columnname) a order by columnname desc
3.如果tablename里没有其他identity列，那么：
select identity(int) id0,* into #temp from tablename
取n到m条的语句为：
select * from #temp where id0 >=n and id0 <= m
如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行：
exec sp_dboption 你的DB名字,'select into/bulkcopy',true
4.如果表里有identity属性，那么简单：
select * from tablename where identitycol between n and m
* 如何删除一个表中重复的记录？
create table a_dist(id int,name varchar(20))
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
insert into a_dist values(1,'abc')
exec up_distinct 'a_dist','id'
select * from a_dist
create procedure up_distinct(@t_name varchar(30),@f_key varchar(30))
--f_key表示是分组字段﹐即主键字段
as
begin
declare @max integer,@id varchar(30) ,@sql varchar(7999) ,@type integer
select @sql = 'declare cur_rows cursor for select '+@f_key+' ,count(*) from ' +@t_name +' group by ' +@f_key +' having count(*) > 1'
exec(@sql)
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
select @type = xtype from syscolumns where id=object_id(@t_name) and name=@f_key
if @type=56
select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+ @id
if @type=167
select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+''''+ @id +''''
exec(@sql)
fetch cur_rows into @id,@max
end
close cur_rows
deallocate cur_rows
set rowcount 0
end
select * from systypes
select * from syscolumns where id = object_id('a_dist')
* 查询数据的最大排序问题（只能用一条语句写）
CREATE TABLE hard (qu char (11) ,co char (11) ,je numeric(3, 0))
insert into hard values ('A','1',3)
insert into hard values ('A','2',4)
insert into hard values ('A','4',2)
insert into hard values ('A','6',9)
insert into hard values ('B','1',4)
insert into hard values ('B','2',5)
insert into hard values ('B','3',6)
insert into hard values ('C','3',4)
insert into hard values ('C','6',7)
insert into hard values ('C','2',3)
要求查询出来的结果如下：
qu co je
----------- ----------- -----
A 6 9
A 2 4
B 3 6
B 2 5
C 6 7
C 3 4
就是要按qu分组，每组中取je最大的前2位！！
而且只能用一句sql语句！！！
select * from hard a where je in (select top 2 je from hard b where a.qu=b.qu order by je)
* 求删除重复记录的sql语句？
怎样把具有相同字段的纪录删除，只留下一条。
例如，表
