xajax的FORM例子
sp; xajax.$(''submitButton'').value="please wait...";
xajax_processForm(xajax.getFormValues("signupForm"));
return false;
}
</script>
</head>
<body>
<div id="formWrapper">
<div id="title">Create a New Account</div>
<div id="formDiv">
<form id="signupForm" action="javascript:void(null);" onsubmit="submitSignup();">
<div>Username:</div><div><input type="text" name="username" /></div>
<div>Password:</div><div><input type="password" name="newPass1" /></div>
<div>Confirm Password:</div><div><input type="password" name="newPass2" /></div>
<div class="submitDiv"><input id="submitButton" type="submit" value="continue ->"/></div>
xajax_processForm(xajax.getFormValues("signupForm"));
return false;
}
</script>
</head>
<body>
<div id="formWrapper">
<div id="title">Create a New Account</div>
<div id="formDiv">
<form id="signupForm" action="javascript:void(null);" onsubmit="submitSignup();">
<div>Username:</div><div><input type="text" name="username" /></div>
<div>Password:</div><div><input type="password" name="newPass1" /></div>
<div>Confirm Password:</div><div><input type="password" name="newPass2" /></div>
<div class="submitDiv"><input id="submitButton" type="submit" value="continue ->"/></div>